Ghani is going o use these instructions to make a fizzy drink. Mix 5 parts of lime juice with 3 parts of lemonade. Ghani thinks that he has 300ml of lime juice and 200ml of leamonade. If Ghani is correct, what is the greatest amount of fizzy that he could make?

Ghani is going o use these instructions to make a fizzy drink. Mix 5 parts of lime juice with 3 parts of lemonade. Ghani thinks that he has 300ml of lime juice and 200 ml of lemonade.

Now, to find the greatest amount of fizzy Ghani could make.

Let the ml of lemonade be [tex]x.[/tex]

As, for making fizzy drink 5 parts of lime juice with 3 parts of lemonade are mixed.

So, 5 is equivalent to 3.

Ghani has 300ml of lime juice.

Thus, 300 is equivalent to [tex]x.[/tex]

Now, to get the ml of lemonade we use cross multiplication method:

[tex]\frac{5}{3} = \frac{300}{x}[/tex]

By cross multiplying we get:

[tex]5x=900[/tex]

Dividing both sides by 5 we get:

[tex]x=180\ ml.[/tex]

Hence, the lemonade is 180 ml.

Now, we add the quantity of 180 ml lemonade with 300 ml lime juice to get the fizzy drink:

[tex]180+300\\\\=480\ ml.[/tex]

Therefore, the greatest amount Ghani could make of fizzy drink is 480 ml.

okpalawalter8 okpalawalter8 · Answer 2 · 2022-04-19T11:21:54+02:00

The greatest amount of fizzy that he could make is

y=480 ml.

What is the greatest amount of fizzy that he could make?

Question Parameter(s):

Mix 5 parts of lime juice with 3 parts of lemonade.

Ghani thinks that he has 300ml of lime juice and 200ml of lemonade

Generally, the lemonade volume is mathematically given as

5/3=300/x

Therefore

x=180 ml.

In conclusion, the quantity of 180 ml of lemonade

y=180+30

y=480 ml.