Answer:
Shear stress
J=0.053431m 4
wp max=48.7 MPa
Kindly find the attached for part b
Explanation:
d0=2.5in=0.0635
di=2.3in=0.05842m
c0=d0/2=0.032m
ci=di/2=0.029
J=π2 (c0 4 −ci 4 )
J=1.5715(0.032 4 −0.029 4 )
J=1.5715(1.05−0.71)x10 −6
J=0.053431m 4
T max =813.5Nm
wp max =T max c0/J
wp max=813.5X0.032/(0.53431X10 −6)
wp max=48.7 MPa