Respuesta :
Answer:
75 minutes
Step-by-step explanation:
In this question, we are asked to calculate the time it will take a smaller hose out of two hoses to fill a swimming pool by itself.
Firstly, let’s say the volume of the swimming pool to fill is Xm^3.
Hence for both, the rate of filling is x/30 m^3/minutes. For the larger hose, rate will be x/50 m^3/minutes. For the larger hose, let the time taken be z minutes. It’s rate will be x/z m^3/minute.
Mathematically, adding both rates together give the rate of both at the same time. This means;
X/30 = x/50 + x/z
X/z = x/30 - c/50
x/z = 20/1500
x/z = 1/75
z = x/75
This means the time that it will take the smaller hose will be 75 minutes
Answer:
75 minutes
Step-by-step explanation:
Let's call the volume of the pool by V.
If the larger hose takes 50 minutes to fill the pool, the amount of water this hose fills is V/50
Let's call the amount of time the small hole takes to fill the pool on its own by T, so its speed is V/T
The two holes together fill the pool in 30 minutes, so their speed summed is V/30:
V/50 + V/T = V/30
Dividing the equation by V, we have:
1/50 + 1/T = 1/30
(3T + 150)/150T = 5T/150T
3T + 150 = 5T
2T = 150
T = 75 minutes
