Answer:
0.1377 is the required probability.
Step-by-step explanation:
We are given the following information in the question:
The number of tracks in an area follow a Poisson distribution.
Mean number of track per area = 6 tracks per [tex]\text{cm}^2[/tex] of surface area.
[tex]\lambda = 6[/tex]
Formula:
[tex]P(x =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}[/tex]
We have to evaluate
P(x = 7)
[tex]P(x = 7)= \displaystyle\frac{\lambda^7 e^{-\lambda}}{7!} = \displaystyle\frac{(6)^7 e^{-6}}{7!}\\\\P(x = 7) = 0.1377[/tex]
0.1377 is the required probability.
