Answer:
The amount of heat flows per second in given aluminium bar is 3.066 [tex]JS^{-1}[/tex].
Explanation:
We know that , amount of heat flowing per second is given by
[tex]\frac{\mathrm{d} Q}{\mathrm{d} t} = \frac{KA\Delta T}{L}[/tex]
Where A = area = [tex]300 mm^{2} = 300\times 10^{-6} m^{2}[/tex]
[tex]\Delta T = 40^{o} c = 40 K[/tex]
K = Thermal conductivity = [tex]230 W/m-k[/tex]
L = Length = [tex]300mm = 300 \times 10^{-3}[/tex]
Upon substituting these values in above equation we get ,
Heat flowing per second = [tex]3.066 JS^{-1}[/tex]
