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Curling is a sport played with 20 kg stones that slide across an ice surface. Suppose a curling stone sliding at 1.5 m/s strikes another stone and comes to rest in 2.5 ms .Approximately how much force is on the stone during impact. 160N 800N 1600N or 8000N


160N

Respuesta :

Olajidey

Answer:

= 12000 N

Explanation:

Using  the formula, we have:

impulse = chenage in momentum

F*t = mV

where,

m = 20kg

t = 2.5ms

= 2.5 × 10⁻³s

v = 1.5m/s

impulse = chenage in momentum

F*t = mV

F = 20*1.5/(2.5x10^-3)

  = 12000 N

Ritmeks

The force of the stone during the impact is 12000 N

The calculation can be done as follows

mass= 20 kg

velocity= 1.5 m/s

t= 2.5ms to secs

= 2.5 × 10⁻³

Force= 20 × 1.5/2.5 × 10⁻3

= 30/2.5 × 2.5×10⁻³

= 12000

Hence the Force on the stone during the impact is 12000 N

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https://brainly.com/question/17538960?referrer=searchResults

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