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A charge of 9.0x10^-5 C is placed in an electric field with a strength of 4.0x10^4 N/C. What is the electrical force acting on the charge

Respuesta :

Answer:

The force is 3.6 Newtons.

Explanation:

The given data is

Charge (q)= [tex]9.0 \times 10^{-5}C[/tex]

Electric field (E)=[tex]4.0 \times 10^{4} N/C[/tex]

Now the formula for electric force is

Force (F) = q E

So ,

[tex]F = 9.0 \times 10^{-5}C \times 4.0 \times 10^{4} N/C[/tex]

Or

[tex]F = 3.6 N[/tex]

Thus the force is 3.6 Newtons

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