Respuesta :
Answer:
The electric field at any point not on either surface is 11.28 N/C.
Explanation:
Given that,
The surface charge density of first sheet, [tex]\sigma_1=+60\ pC/m^2=60\times 10^{-12}C/m^2[/tex]
The surface charge density of second sheet, [tex]\sigma_2=-80\ pC/m^2=-80\times 10^{-12}C/m^2[/tex]
The relation between the electric field and the surface charge density is given by :
[tex]E=\dfrac{\sigma}{\epsilon_o}[/tex]
For first sheet :
[tex]E_1=\dfrac{\sigma_1}{\epsilon_o}\\\\E_1=\dfrac{60\times 10^{-12}}{8.85\times 10^{-12}}\\\\E_1=6.77\ N/C[/tex]
For second sheet,
[tex]E_2=\dfrac{\sigma_2}{\epsilon_o}\\\\E_2=\dfrac{-80\times 10^{-12}}{8.85\times 10^{-12}}\\\\E_2=-9.03\ N/C[/tex]
The net magnitude of the electric field at any point not on either surface is given by :
[tex]E=\sqrt{E_1^2+E_2^2} \\\\E=\sqrt{(6.77)^2+(-9.03)^2} \\\\E=11.28\ N/C[/tex]
So, the electric field at any point not on either surface is 11.28 N/C.
