Answer:
The net charge within the cylinder is (-44.25 pC)
Explanation:
Given that,
Total electric flux, [tex]\phi=-5\ N-m^2/C[/tex]
Length of the cylinder, l = 1.2 m
Diameter of the cylinder, d = 0.2 m
We know that the Gauss's law of electrostatics gives the relation between electric flux and the net charge. It is given by :
[tex]\phi=\dfrac{q}{\epsilon_o}[/tex]
q is net charge within the cylinder
[tex]q=\phi\times \epsilon_o\\\\q=-5\times 8.85\times 10^{-12}\\\\q=-44.25\times 10^{-12}\ C\\\\q=-44.25\ pC[/tex]
So, the net charge within the cylinder is (-44.25 pC). Hence, this is the required solution.
