Answer:
The average velocity is
[tex]\dfrac{128}{3}\text{ feet per second}[/tex]
Step-by-step explanation:
We are given the following in the question:
[tex]y(t) = 8t^2[/tex]
where y(t) is the distance in feet in first t seconds.
Average rate of change =
[tex]\dfrac{y(t_2)-y(t_1)}{t_2 - t_1}[/tex]
a) average rate of change of distance with respect to time from 2 to 5 seconds
Putting values, we get,
Average velocity =
[tex]\dfrac{y(5) - y(2)}{5-2} = \dfrac{8(25-9)}{5-2} = \dfrac{128}{3}\text{ feet per second}[/tex]
Thus, the average velocity is
[tex]\dfrac{128}{3}\text{ feet per second}[/tex]
