Answer:
It will be 4 times larger.
Step-by-step explanation:
The radius of a fluorine atom is about [tex]5 \times 10^{- 8}[/tex] mm. and the radius of a strontium atom is about [tex]2 \times 10^{- 7}[/tex] mm.
We have to calculate the number of times larger the radius of a strontium atom than the radius of a fluorine atom.
We will get the number by dividing the radius of a strontium atom by the radius of a fluorine atom.
Hence, it will be [tex]\frac{2 \times 10^{- 7} }{5 \times 10^{- 8}} = \frac{20}{5} = 4[/tex] times larger. (Answer)
