Answer: The concentration of A after 865 seconds is 0.00125 M
Explanation:
The integrated rate law equation for second order reaction follows:
[tex]k=\frac{1}{t}\left (\frac{1}{[A]}-\frac{1}{[A]_o}\right)[/tex]
where,
k = rate constant = [tex]0.660M^{-1}s^{-1}[/tex]
t = time taken = 865 second
[A] = concentration of substance after time 't' = ?
[tex][A]_o[/tex] = Initial concentration = 0.00440 M
Putting values in above equation, we get:
[tex]0.660=\frac{1}{865}\left (\frac{1}{[A]}-\frac{1}{(0.00440)}\right)[/tex]
[tex][A]=0.00125M[/tex]
Hence, the concentration of A after 865 seconds is 0.00125 M
