Respuesta :
Answer:
Explanation:
def octal_to_string(octal):
  result = ''
  value_letters = [(4, 'r'), (2, 'w'), (1, 'x')]
  for c in [int(n) for n in str(octal)]:
    for value, letter in value_letters:
      if c >= value:
        result += letter
        c -= value
      else:
        result += '-'
  return result
print(octal_to_string(755))
print(octal_to_string(644))
print(octal_to_string(750))
print(octal_to_string(600))
**************************************************
In this exercise, using the knowledge of computational language in linux, we have that this code will be written as:
The code is in the attached image.
We can write the linux as:
 result = ''
 value_letters = [(4, 'r'), (2, 'w'), (1, 'x')]
 for c in [int(n) for n in str(octal)]:
   for value, letter in value_letters:
     if c >= value:
       result += letter
       c -= value
     else:
       result += '-'
 return result
print(octal_to_string(755))
print(octal_to_string(644))
print(octal_to_string(750))
print(octal_to_string(600))
See more about linux at brainly.com/question/15122141
