Answer:
Step-by-step explanation:
The way I figured this out is to just pick some starting values for the grams of this element and plug them into the formula using t = 1 day and seeing how much is left. I chose 2 different starting amounts and came up with the same percentage each time, so it must be correct! Here's what I did:
First I chose a starting amount, a, of 10 grams. Plugging into the formula:
[tex]y=10(.5)^{\frac{1}{14} }[/tex]
and got that the amount LEFT was 9.5 grams
Then I chose a starting amount, a, of 20 grams. Plugging into the formula:
[tex]y=20(.5)^{\frac{1}{14}}[/tex]
and got that the amount LEFT was 19 grams.
I then asked the algebraic question,"What percent of 10 is 9.5?" which translates to
x% * 10 = 9.5 and
x = 95% (that's the amount left as a percentage).
and
x% * 20 = 19 and
x = 95%
Since both of those came out the same, that tells me that after 1 day there is still 95% of the element remaining, so 5% decays each day.
