Respuesta :
Answer : The value of 'K' is, [tex]1.78\times 10^{4}[/tex]
Explanation :
The copper(II) ion reacts with phosphate ion to form an insoluble ionic compound.
(1) The chemical reaction will be:
[tex]Cu_3(PO_4)_2\rightleftharpoons 3Cu^{2+}+2PO_4^{3-}[/tex]
[tex]K_{sp}=1.40\times 10^{-37}[/tex]
The copper(II) ion also forms a complex ion with ammonia.
(2) The chemical reaction will be:
[tex]Cu^{2+}+4NH_3\rightarrow [Cu(NH_3)_4]^{2+}[/tex]
[tex]K_f=5.03\times 10^{13}[/tex]
To calculate the value of 'K' we are multiplying reaction 2 by 3, we get:
(3) [tex]3Cu^{2+}+12NH_3\rightarrow 3[Cu(NH_3)_4]^{2+}[/tex]
[tex]K_f'=(K_f)^3=(5.03\times 10^{13})^3[/tex]
Now we are adding reaction 1 and 3, we get:
[tex]Cu_3(PO_4)_2+12NH_3\rightarrow [Cu(NH_3)_4]^{2+}+2PO_4^{3-}[/tex]
[tex]K=K_f'\times K_{sp}[/tex]
[tex]K=(5.03\times 10^{13})^3\times (1.40\times 10^{-37})[/tex]
[tex]K=1.78\times 10^{4}[/tex]
Therefore, the value of 'K' is, [tex]1.78\times 10^{4}[/tex]
