A string is stretched to a length of 339 cm and both ends are fixed. If the density of the string is 0.0073 g/cm, and its tension is 859 N, what is the fundamental frequency?

Respuesta :

Answer:

160 Hz.

Explanation:

For nth harmonic, the fundamental frequency,

[tex]f_n=\frac{n}{2L}\sqrt{\frac{T}{\mu} }[/tex]

Here T is the tension in string, \mu is the mass/unit of length of the string and L is the string length.

Given n = 1  frequency of the 1st harmonic (the Fundamental), T = 859 N,

L= 339 cm =3.39 m and [tex]\mu=0.0073 g/cm =0.00073 kg /m[/tex].

Substituting these values, we get

[tex]f_1=\frac{1}{2\times3.39m} \sqrt{\frac{859N}{0.00073\ kg/m } }[/tex]

[tex]f_1= 0.147 \times1084.76=159.99 Hz[/tex]

[tex]f_1=160 Hz[/tex]

Thus, the fundamental frequency is 160 Hz.