Answer:
At 320 nm, %T = 70.79 %
At 280 nm, %T = 5.01 %
Explanation:
The absorption values and the percent transmission is linked with the expression bellow;
A = 2 - log %T
Where A is the Absorption value = 0.15 and 1.3 respectively;
%T is the percent transmission.
At 320 nm, A = 0.15
0.15 = 2- log T
Log T = 2-0.15
Log T = 1.85
T = Anti log 1.85
T = 70.79 %
Therefore the percent transmission at 230 nm is 70.79 %
At 280 nm A = 1.3
1.3 = 2 - log T
Log T = 2 - 1.3
Log T = 0.7
T = anti log 0.7
T = 5.01 %
Therefore the percent transmission at 280 nm is 5.01 %
