Analyze the following code:
public class Test {
public static void main(String[] args) {int[] x = {1, 2, 3, 4, 5};xMethod(x, 5);}public static void xMethod(int[] x, int length) {
System.out.print(" " + x[length - 1]);xMethod(x, length - 1);}}
The program displays 1 2 3 4 6.
The program displays 1 2 3 4 5 and then raises an Array Index Out Of Bounds Exception.
The program displays 5 4 3 2 1.
The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

Question

25-03-2020
Computers and Technology

contestada

Analyze the following code:
public class Test {
public static void main(String[] args) {int[] x = {1, 2, 3, 4, 5};xMethod(x, 5);}public static void xMethod(int[] x, int length) {
System.out.print(" " + x[length - 1]);xMethod(x, length - 1);}}
The program displays 1 2 3 4 6.
The program displays 1 2 3 4 5 and then raises an Array Index Out Of Bounds Exception.
The program displays 5 4 3 2 1.
The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

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ibnahmadbello ibnahmadbello · Answer 1 · 2020-03-28T02:06:57+01:00

Answer:

The program displays 5 4 3 2 1 and then raises an Array Index Out Of Bounds Exception.

Explanation:

A sample of code output is attached.

The code snippet contain xMethod that takes an array and array length as argument.

In the given snippet, the array {1, 2, 3, 4, 5} and length (5) is passed as argument to the method.

First the method display the element of the array in reverse order

System.out.print(" " + x[length - 1]);

and then the method call itself again. This displays

5 from x[4]

4 from x[3]

3 from x[2]

2 from x[1]

1 from x[0]

but after displaying 1, when it tries to call the method again, an array index out of bound exception is thrown because it will try accessing an element from the array when it is already exhausted.