Answer:
The [tex]6.25 \times 10^{23}[/tex] electrons are moving through the superconductor per second.
Explanation:
Given :
Current [tex]I = 1 \times 10^{5}[/tex] A
Charge of electron [tex]e = 1.6 \times 10^{-19}[/tex] C
Time [tex]t = 1[/tex] sec
From the formula of current,
Current is the number of charges flowing per unit time.
[tex]I = \frac{ne}{t}[/tex]
Where [tex]n =[/tex] number of charges means in our case number of electrons
[tex]n = \frac{It}{e}[/tex]
[tex]n = \frac{1 \times 10^{5} }{1.6 \times 10^{-19} }[/tex]
[tex]n = 6.25 \times 10^{23}[/tex]
Therefore, [tex]6.25 \times 10^{23}[/tex] electrons are moving through the superconductor per second.