Answer:
no enough evidence to draw up a conclusion
Step-by-step explanation:
Data:
let: [tex]\mu _{1}[/tex] = decay after 2 weeks
  [tex]\mu _{2}[/tex] = decay after 16 weeks
Making the hypotheses:
Null hypothesis; [tex]H_{o} = \mu _{1} - \mu _{2} = 0[/tex]
the deviation = 0.05
the standard difference  = 4
Conditions:
The normal distribution curve can be plotted on a graph and the plot shows that the distribution is a skewed distribution.
Then,
[tex]t = \frac{(123.8-16.4)-0}{\sqrt{\frac{4.6^{2} }{5}+\frac{16.09^{2} }{5} } } \\ = 0.989[/tex]
Therefore, it can be concluded that 0.1983 > 0.05. This presents our failure to reject the null hypothesis.
Thus, there is not enough evidence to conclude that polyester decays more in less than 2 weeks.
The p-value computed shows that there's no enough evidence to show that polyester decays more in less than 2 weeks.
It should be noted that a p-value simply means a measure of the probability that an observed difference could have taken place by random chance.
In this case, the t-statistic is calculated as:
= [(123.8 - 16.4) / (✓4.6²/5 + ✓16.09²/5)]
= 0.989
The p value is also deduced as 0.1983. Therefore, since 0.1983 is more than 0.05, we fail to reject the null hypothesis.
This implies that there is no enough evidence to show that polyester decays more in less than 2 weeks.
Learn more about p-value on:
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