Respuesta :
Answer:
distance = 21.56 m
Explanation:
given data
mass = 50 kg
initial velocity = 18.2 m/s
force = -200 N ( here force applied to opposite direction )
final velocity = 12.6 m/s
solution
we know here acceleration will be as
acceleration a = force ÷ mass
a = [tex]\frac{-200}{50}[/tex] = -4 m/s²
we get here now required time that is
required time = [tex]\frac{V_{(final)} - V_{(initial)}}{a}[/tex] ...............1
put here value
required time = [tex]\frac{12.6-18.2}{-4}[/tex]
so distance will be
distance = [tex]\frac{V_{(final)}^2 - V_{(initial)}^2}{2a}[/tex] ........2
distance = [tex]\frac{12.6}^2 -{18.2}^2}{2\times (-4)}[/tex]
distance = 21.56 m
The amount of time this force was applied on the object is equal to 1.4 seconds.
Given the following data:
- Force = 200 Newton
- Mass of object = 50.0 kg
- Final velocity = 18.2 m/s
- Initial velocity = 12.6 m/s.
To determine how long (time) this force was applied, we would apply Newton's Second Law of Motion:
Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the force acting on the object and inversely proportional to its mass.
Mathematically, Newton's Second Law of Motion is given by this formula;
[tex]Force = mass \times acceleration[/tex]
Also, the acceleration of an object is equal to the rate of change in velocity with respect to time.
So, Newton's Second Law of Motion becomes:
[tex]F = \frac{M(v\;-\;u)}{t}[/tex]
Making t the subject of formula, we have:
[tex]t = \frac{M(v\;-\;u)}{F}[/tex]
Substituting the given parameters into the formula, we have;
[tex]t = \frac{50(18.2\;-\;12.6)}{200}\\\\t = \frac{50(5.6)}{200}[/tex]
Time, t = 1.4 seconds
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