Answer:
26.56°
Explanation:
μ= 0.5
F = ?
N =?
Fs = μN
Fs = force acting due to friction (on an inclined plane)
N = normal force.
μ= coefficient of friction
μ= tanΘ
μ= tan 0.5
Θ = tan⁻¹ 0.5
Θ = 26.56°
The angle in which is required for the box to start moving across the inclined plane is 26.56°