Answer:
(c) the equilibrium partial pressure of [tex]BrCl(g)[/tex] will be greater than [tex]2.00[/tex] atm.
Explanation:
Equilibrium constant of the given reaction will be as follows,
[tex]Q_{p} =\frac{[products]}{[reactants]}[/tex]
Therefore, according to the equation
[tex]Q_{p} = \frac{[2.00]^2}{{[1.00]}[1.00]}[/tex]
[tex]Q_{p}= 4[/tex]
Since [tex]K_{p}=7.0[/tex]
[tex]Q_{p} < K_{p}[/tex].
Since the reaction is moving n forward direction so the pressure will be increasing at equilibrium as compared to the initial pressure.
Also, the reaction is in equilibrium so it cannot be considered to be at completion.
So, option (c) the equilibrium pressure is of [tex]BrCl(g)[/tex] will be greater than [tex]2.00[/tex] atm is correct.