Answer: m = 74.7 g Ca(OH)2
Explanation: To solve this problem we will use the formula for Molarity which is M = n /L, where n is the number of moles and L represents volume in liters. Derive for n to find moles then convert it to mass using the molar mass of the compound.
First convert mL to L
532.0 mL ( 1 L / 1000 mL ) = 0.532 L
n = M L
= 1.90 M ( 0.532 L )
= 1.01 moles Ca(OH)2
Convert moles to mass:
= 1.01 moles Ca(OH)2 x 74 g Ca(OH)2 / 1 mole Ca(OH)2
= 74.7 g Ca(OH)2
