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A picture measuring 2 inches by 3 inches is placed inside a frame. The width between the picture and the frame is equal around the entire picture. If the area of the frame and the picture is 72 square inches, what is the width of the frame? (This is my last question for my homework, so quick help would be appreciated :D).

Respuesta :

Answer:

3 inches

Step-by-step explanation:

(2 + 2x)(3 + 2x) = 72

4x² + 4x + 6x + 6 - 72 = 0

4x² + 10x - 66 = 0

2x² + 5x - 33 = 0

Using quadratic formula:

x = (-5-17)/4, (-5+17)/4

x = 12/4 = 3

The width of the given photo frame is required.

The width of the frame is 3 inches.

Length of picture = 3 inches

Width of picture = 2 inches

x = Thickness of frame

Length of frame with photo = [tex]3+2x[/tex]

Width of frame with photo = [tex]2+2x[/tex]

The area of frame and picture = 72 square inches

Area is given by

[tex](3+2x)(2+2x)=72\\\Rightarrow 6+6x+4x+4x^2=72\\\Rightarrow 4x^2+10x-66=0\\\Rightarrow x=\dfrac{-10\pm \sqrt{10^2-4\times4\left(-66\right)}}{2\times4}\\\Rightarrow x=3,-\dfrac{11}{2}[/tex]

The width of the frame is 3 inches.

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