two identical regular hexagons are joined together as shown in a diagram.
work out the size of angle x

Answer:
[tex]x=120^o[/tex]
Step-by-step explanation:
step 1
Find the measure of the interior angle in a regular hexagon
we know that
The formula to calculate the measure of the interior angle in a regular polygon is equal to
[tex]\frac{(n-2)180^o}{n}[/tex]
where
n is the number of sides of polygon
In this problem
n=6
so
[tex]\frac{(6-2)180^o}{6}=120^o[/tex]
step 2
Find the measure of angle x
we know that
[tex]x+120^o+120^o=360^o[/tex] ----> by complete circle
solve for x
[tex]x=360^o-240^o=120^o[/tex]
Each interior angle of a regular hexagon is 120°
The size of angle x is 120°.
We know that, each interior angle of a regular hexagon is 120°.
∴ ∠AOC = ∠BOC =120°
Let point 'O' is a complete angle.
Then, ∠O =360°
∠AOC +∠BOC + x = 360°
120° + 120° + x = 360°
x = 360° - 240°
x = 120°
Therefore, the size of angle x is 120°.
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