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Short man with curly hair and normal hearing marry on short woman with straight hair and normal hearing. What kind of children can be by this marriage if we know what mother of man was short, smooth-haired and deaf but father had normal stature, curly hair and normal hearing; mother of woman had normal hearing, short stature and normal hearing but her father was deaf had normal stature and curly hair? Curly hair, normal hearing and short stature is dominant traits.

Respuesta :

Answer:

Ss × Ss= SS, Ss, Ss , ss,= 3/4 are short stature  and 1/4 are normal stature;

Cc × cc= Cc, Cc, cc, cc= 1/2 are curly hair and 1/2 are straight hair;

Dd × Dd= DD, Dd, Dd, dd= 3/4 are normal hearing, 1/2 are deaf.

Explanation:

1.  As given

    C= curly hear, C is dominant over c;

    D= normal hearing, D is dominant over d;

    S= short stature, S is dominant n;

2. As given, by the parents of man and women , the genotype of man is SsCcDd (short stature, curly hear, and normal hearing). Genotype of woman is  SsccDd (  short stature,straight hari and normal hearing.

3. Cross between both parents;  SsCcDd  and SsccDd

4. Progeny are ; as

Ss × Ss= SS, Ss, Ss , ss,= 3/4 are short stature  and 1/4 are normal stature;

Cc × cc= Cc, Cc, cc, cc= 1/2 are curly hair and 1/2 are straight hair;

Dd × Dd= DD, Dd, Dd, dd= 3/4 are normal hearing, 1/2 are deaf.

5.So, we can calculate;

3/4 × 1/2× 3/4 = 9/32 are short stature, curly hair and normal hearing.

3/4 × 1/2 × 3/4 =9/32 are short stature, straight hair and normal hearing.

3/4 × 1/2 × 1/2=3/16 are  short stature,  curly hair and deaf.

3/4 × 1/2 × 1/2= 3/16  are short stature, straight hair and deaf.

1/4 × 1/2× 3/4 =3/32 are normal stature, curly hair and normal hearing.

1/4 ×  1/2 × 3/4=3/32 are normal stature, straight hair and normal hearing.

1/4 ×  1/2 × 1/2=1/16  are normal stature, curly hair and deaf.

1/4 ×  1/2 ×  1/2 =1/16 are normal stature, straight hair and deaf.

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