Answer:
0.03atm
Explanation:
Given parameters:
Total pressure = 780torr
Partial pressure of water vapor = 1.0atm
Unknown:
Partial pressure of radon = ?
Solution:
A sound knowledge of Dalton's law of partial pressure will help solve this problem.
The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".
Mathematically;
P[tex]_{t}[/tex] = P[tex]_{1}[/tex] + P[tex]_{2}[/tex] + P[tex]_{n}[/tex]
Since the total pressure is 780torr, convert this to atm;
760torr = 1 atm
780torr = [tex]\frac{780}{760}[/tex] atm = 1.03atm
For this problem;
Total pressure = Partial pressure of radon + Partial pressure of water vapor
1.03 = Partial pressure of radon + 1.0
Partial pressure of radon = 1.03 - 1.00 = 0.03atm
