Answer:
0.28moles of Al₂O₃
Explanation:
Given parameters:
Mass of Al = 14.9g
Unknown:
Number of moles of Al₂O₃ = ?
Solution:
Let us write the reaction equation first;
4Al + 3O₂ → 2Al₂O₃
Now that we have obtained the balanced equation, we work from the known to the unknown. The known is the mass of Al.
Find the number of moles in this mass;
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of Al = 27g/mol
Number of moles = [tex]\frac{14.9}{27}[/tex] = 0.55moles
From the balanced reaction equation;
4 moles of Al will produce 2 moles of Al₂O₃
0.55 moles of Al will produce [tex]\frac{0.55 x 2}{4}[/tex] = 0.28moles of Al₂O₃
