Answer:
3.72L
Explanation:
Given parameters:
Initial volume V₁ = 3.9L
Condition = STP
Final temperature T₂ = -550°C
Final pressure P₂ = 880mmHg
Unknown:
Final volume V₂ = ?
Solution.
At standard temperature and pressure(STP), the:
Pressure = 1atm = 760mmHg
Temperature = 273K
Therefore, P₁ = 760mmHg
T₁ = 273K
The general gas law, is best to solve this problem. It is mathematically given as:
[tex]\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }[/tex]
Let us take the units to the appropriate one;
-550°C = 273 + (-550) = -277K
Input the variables;
[tex]\frac{760 x 3.9}{273} = \frac{808 x V_{2} }{-277}[/tex]
V₂ = 3.72L
