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Which is a possible equation of a parabola that intersects the x-axis at points (-1,0) and (3,0)? Question 2 options: y=x2+3x−3 y=x2−3x+2 y=x2−2x−3 y=x2+3x+2

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Answer:

Step-by-step explanation:

Where a graph intersects the x-axis is where the solutions or zeros of the quadratic are found...where y = 0.

If the points of intersection are x = -1 and x = 3, then putting those into factors gives us (x + 1)(x - 3) = 0.  FOIL that out to get the quadratic.

[tex]x^2-3x+x-3[/tex] which simplifies to

[tex]x^2-2x-3=y[/tex]

Looks like the third option there.

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