Respuesta :
Answer:
The average acceleration of the flowerpot will be [tex]9.8m/s^2[/tex] .
Explanation:
The average acceleration is equal to change in velocity divided by change in time in given interval.
[tex]a=\frac{v-u}{\Delta t}[/tex]
Here v is the final velocity and u is the initial velocity.
Given v = 14.7 m/s, u = 0 (as flowerpot falls off a second story windowsill) and [tex]\Delta t= 1.5 s[/tex] .
Substitute the given values, we get
[tex]a=\frac{14.7m/s-0}{1.5s}[/tex]
[tex]a=9.8m/s^2[/tex]
Thus, the average acceleration of the flowerpot will be [tex]9.8m/s^2[/tex] .
