Answer:
Image will form at distance 22.22 cm behind the mirror
Explanation:
As we know that the mirror formula is given as
[tex]\frac{1}{d_i} + \frac{1}{d_o} = \frac{1}{f}[/tex]
now we know that
object distance from mirror is
[tex]d_o = -50 cm[/tex]
Focal length of the mirror is given as
[tex]f = 40 cm[/tex]
now we have
[tex]\frac{1}{-50} + \frac{1}{d_i} = \frac{1}{40}[/tex]
[tex]\frac{1}{d_i} = \frac{1}{50} + \frac{1}{40}[/tex]
[tex]d_i = 22.22 cm[/tex]
