Answer:
Total time taken by the heater to raise the temperature of water is 335 s
Explanation:
As we know that the heat required to raise the temperature of water is given as
[tex]Q = ms\Delta T[/tex]
here we know that
m = 40 kg
s = 4186 J/kg C
now its temperature is raised from 40 degree to 80 degree
so we will have
[tex]Q = 40(4186)(80 - 40)[/tex]
[tex]Q = 6.69 \times 10^6 J[/tex]
Now we know that the power of the heater is 20 kW
so total time taken by the heater to raise the temperature of water is given as
[tex]t = \frac{Q}{P}[/tex]
[tex]t = \frac{6.69 \times 10^6}{20 \times 10^3}[/tex]
[tex]t = 335 s[/tex]