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A quadratic equation is shown:
x2 - 14x + 41 = 0
Which of the following is the first correct step to write the above equation in the form (x - p)2 = 9, where p and q are integers?
x2 - 14x + 41 + 8 = 0 + 8
x2 - 14x + 41 + 9 = 0 + 9
x2 - 14x + 41 - 8 = 0 - 8
x2 – 14x + 41 - 9 = 0 - 9

Respuesta :

Answer:

The correct answer is the first option

Step-by-step explanation:

Quadratic Equation

The standard form of a quadratic equation is

[tex]ax^2+bx+c=0[/tex]

Sometimes we need to change the expression of the same equation to the form

[tex](x-p)^2=q[/tex]

To accomplish that change, we usually modify the left-hand expression to make it look like the square of a binomial.

The given quadratic equation is

[tex]x^2-14x+41=0[/tex]

Recall the square of a binomial is

[tex](x-p)^2=x^2-2px+p^2[/tex]

The first term is already present. The second term gives us the value of p:

[tex]-2px=-14x[/tex]

Solving

[tex]p=7[/tex]

Now we need to produce the third term [tex]p^2=49[/tex]. We only have 41, thus we need to add 8 to both sides of the equation:

[tex]x^2-14x+41+8=0+8[/tex]

The correct answer is the first option