Explanation:
Given that,
Speed of a motorcycle, v = 27.8 m/s
Radius of curvature of the path, r = 192 m
The mass of the motorcycle and driver is 323 kg, m = 323 kg
(a) The centripetal force acting on the motorcycle is given by :
[tex]F=\dfrac{mv^2}{r}\\\\F=\dfrac{323\times (27.8)^2}{192}\\\\F=1300.14\ m/s^2[/tex]
The centripetal force is [tex]1300.14\ m/s^2[/tex].
(b) The normal force acting on the cycle is given by :
[tex]N=mg-F\\\\N=323\times 9.8-1300.14\\\\N=1865.26\ N[/tex]
Hence, this is the required solution.
