if triangle jkl is similar to triangle nml find the values of x and y

Answer:
y=18
x=35
Step-by-step explanation:
Scale factor is 2.5
40/16
14*2.5
16/2.5
45/2.5 gives you y
The value of x is 35 and the value of y is 18.
Two triangles will be similar if the corresponding angles are equal and corresponding sides are in the same ratio. Similar triangles may have different individual lengths of sides but their angles must be equal.
Here, in the given problem, ΔJKL ~ ΔNML , i.e. ΔJKL is similar to ΔNML.
In ΔJKL, KJ=40, LJ=45, KL=x
In ΔNML, NM=16, LN=y, LM=14
Comparing the corresponding sides,
[tex]\frac{KJ}{NM}=\frac{KL}{LM}[/tex]
⇒[tex]\frac{40}{16}=\frac{x}{14}[/tex]
⇒[tex]x=\frac{40*14}{16}[/tex]
⇒[tex]x=35[/tex]
Again, comparing the corresponding sides,
[tex]\frac{KJ}{NM} =\frac{LJ}{LN}[/tex]
⇒[tex]\frac{40}{16}=\frac{45}{y}[/tex]
⇒[tex]y=\frac{45*16}{40}[/tex]
⇒[tex]y=18[/tex]
∴ x=35 and y=18
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