Respuesta :
Answer: The molecular formula will be [tex]CF_4[/tex]
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C= 13.65 g
Mass of F = 86.35 g
Step 1 : convert given masses into moles.
Moles of C =[tex]\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{13.65g}{12g/mole}=1.138moles[/tex]
Moles of F=[tex]\frac{\text{ given mass of F}}{\text{ molar mass of F}}= \frac{86.35g}{19g/mole}=4.545moles[/tex]
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C = [tex]\frac{1.138}{1.138}=1[/tex]
For F = [tex]\frac{4.545}{1.138}=4[/tex]
The ratio of C : F= 1: 4
Hence the empirical formula is [tex]CF_4[/tex]
The empirical weight of [tex]CF[/tex] = 1(12)+4(19)= 88g.
The molecular weight = 88.01 g/mole
Now we have to calculate the molecular formula.
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{88.01}{88}=[/tex]
The molecular formula will be=[tex]1\times CF_4=CF_4[/tex]
