Respuesta :
Answer: The amount of heat required to warm given amount of water is 470.9 kJ
Explanation:
To calculate the mass of water, we use the equation:
[tex]\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}[/tex]
Density of water = 1 g/mL
Volume of water = 1.50 L = 1500 mL (Conversion factor: 1 L = 1000 mL)
Putting values in above equation, we get:
[tex]1g/mL=\frac{\text{Mass of water}}{1500mL}\\\\\text{Mass of water}=(1g/mL\times 1500mL)=1500g[/tex]
To calculate the heat absorbed by the water, we use the equation:
[tex]q=mc\Delta T[/tex]
where,
q = heat absorbed
m = mass of water = 1500 g
c = heat capacity of water = 4.186 J/g°C
[tex]\Delta T[/tex] = change in temperature = [tex]T_2-T_1=(100-25)^oC=75^oC[/tex]
Putting values in above equation, we get:
[tex]q=1500g\times 4.186J/g^oC\times 75^oC=470925J=470.9kJ[/tex]
Hence, the amount of heat required to warm given amount of water is 470.9 kJ
Taking into account the definition of calorimetry, the amount of heat required is 470,925 J.
In first place, calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system. In this way, between heat and temperature there is a direct proportional relationship.
The constant of proportionality depends on the substance that constitutes the body and its mass, and is the product of the specific heat by the mass of the body.
So, the equation that allows to calculate heat exchanges is:
Q = c× m× ΔT
where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.
On the other side, density is a quantity that allows us to measure the amount of mass in a certain volume of a substance. Then, the expression for the calculation of density is the quotient between the mass of a body and the volume it occupies:
[tex]density=\frac{mass}{volume}[/tex]
Then, you know:
- Q= ?
- c= 4.186[tex]\frac{J}{gC}[/tex]
- m= density× volume= 1 [tex]\frac{g}{mL}[/tex]×1500 mL (being 1.5 L=1500 mL) → m=1500 g
- ΔT= Tfinal - Tinitial= 100 C - 25 C= 75 C
Replacing in the expression to calculate heat exchanges:
Q= 4.186 [tex]\frac{J}{gC}[/tex]× 1500 g× 75 C
Solving:
Q= 470,925 J
In summary, the amount of heat required is 470,925 J.
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