Answer:
The information necessary would be Nos. 1 (milligrams of Ca), 2 (molar mass of hydroxide) and 4 (molar mass of Calcium)
Explanation:
The calculation of the moles of hydroxide would be the usual stoichiometric calculations, where all that is required is the mass and molar mass of reactants and products, depending on the variable in question. Hence, volume and molarity are not necessarily required to determine amount of product.
The information necessary would be Nos. 1 (milligrams of Ca), 2 (molar mass of hydroxide) and 4 (molar mass of Calcium)
The reaction equation is:
[tex]Ca(OH)_{2}[/tex] → [tex]Ca^{2+}[/tex] + [tex]2 OH^{-}[/tex]
N.B. Calcium hydroxide only slightly dissolves in water to form as lightly basic solution; the solubility is increased by increase in temperature.
