Answer:
y = C1x^(-1/2) cosx + C2x^(-1/2) sinx
Step-by-step explanation:
Given that
y1 = x^(-1/2) cosx
y2 = x^(-1/2) sinx
are linearly independent solutions of the nonhomogeneous equation
x²y'' + xy' + x² − 1 4y = x^(3/2)
Then the general equation of the differential equation can be written as
y = C1y1 + C2y2
y = C1x^(-1/2) cosx + C2x^(-1/2) sinx