Step-by-step explanation:
Quadrilateral ABCD is inscribed in a circle.
Opposite angles of a Quadrilateral are Supplementary.
[tex] \therefore \: \angle A + \angle C = 180° \\ \therefore \:(2x + 3) \degree+ (2x + 1) \degree = 180° \\ \therefore \: (4x + 4) \degree = 180° \\ \therefore \: (4x + 4) = 180 \\ \therefore \: 4x = 180 - 4 \\ \therefore \: 4x = 176 \\ \therefore \: x = \frac{176}{4} \\ \therefore \: x = 44 \\ \\ m\angle A = (2x + 3) \degree \\ = (2 \times 44 + 3) \degree \\ = (88 + 3) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle A =91 \degree}} \\ \\ m\angle C = (2x + 1) \degree \\ = (2 \times 44 + 1) \degree \\ = (88 + 1) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle C=89\degree}} \\ \\ m\angle D= (x - 10) \degree \\ = (44 - 10) \degree \\ \huge \red{ \boxed{ \therefore \: m\angle D =34\degree}} \\ \\ similarly \\ \\ \huge \red{ \boxed{ \therefore \: m\angle B = 146\degree}} \\ \\ [/tex]
