Complete Question
The complete question is is shown on the first uploaded
Answer:
The elastic potential energy at point B is [tex]PE_{elastic} = 50J[/tex]
The kinetic energy at point D is [tex]KE = 75J[/tex]
Explanation:
Looking at the given point we can observe that mechanically energy(i.e potential and kinetic energy ) is conserved and it value is [tex]E_ {m} = 100J[/tex]
So at point B
[tex]E_{m} = PE_{elastic} +KE[/tex]
[tex]100 = PE_{elastic} + KE[/tex]
KE at point B is 50J
So [tex]PE_{elastic} = 100 - 50 = 50J[/tex]
Now at point D
[tex]E_{m} = PE_{elastic} +KE[/tex]
[tex]PE_{elastic}[/tex] at point D is 25J
So [tex]KE = 100 - 25 = 75J[/tex]