for the oxidation of glucose C6 H12 O6 + 602 -- 6H2O + 6C02, How many moles of oxygen will it take to consume 3.9 moles of glucose C6 H12 O6?
27
.12
.65
23.4

Respuesta :

Answer:

The answer to your question is 23.4 moles of Glucose

Explanation:

Data

moles of Oxygen = ?

moles of glucose = 3.9

-Balanced chemical reaction

           1C₆H₁₂O₆  +  6O₂   ⇒   6H₂O  +  6CO₂

Process

1.- To solve this problem, use the coefficient of the balanced chemical equation, and use proportions and cross multiplication.

           1 mol of C₆H₁₂O₆ -------------------- 6 moles of O₂

    3.9 moles of C₆H₁₂O₆ ------------------   x

                                  x = (3.9 x 6 ) / 1

                                  x = 23.4 moles

2.- Conclusion

3.9 moles of glucose consume 23.4 moles of oxygen