Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end of a rope is attached to the bus and the other is tied around Magnus's waist. If a force gauge placed halfway down the rope reads out a constant 2750 2750 Newtons while Magnus pulls the bus a distance of 1.60 1.60 meters, how much work does the tension force do on Magnus? The rope is perfectly horizontal during the pull.

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okpalawalter8 okpalawalter8 · Answer 1 · 2020-03-29T04:37:05+02:00

Answer:

The workdone is [tex]W_d =-4400J[/tex]

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

The force is on the force gauge [tex]F = 2750 N[/tex]

The distance that Magnus pulled the bus [tex]d = 1.60m[/tex]

Generally the workdone by the tension force on Magnus is

[tex]Workdone = Force * displacement \ in \ the \ direction \ of \ force[/tex]

[tex]W_d = F * (-d)[/tex]

This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

[tex]Workdone = - 2750 * 1.60[/tex]

[tex]=-4400 J[/tex]