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A sample of 25 measurements on a normally distributed quality characteristic has a mean of 85 and a standard deviation of 1. Using a confidence probability of 0.95, find a value such that 90% of the future measurements on this quality characteristic will lie above it?

Respuesta :

thaovtp1407

Answer:

Step-by-step explanation:

Given that:

  • n = 25
  • α = 0.01
  • γ = 0.95 one sided
  • x ~ N (85, 1)

From Appendix VIII: K= 1.838

So: x - KS = 85 - 1.838(1)  = 83.162

Hope it will find you well

Parrain

Based on the sample size, the mean, and the confidence probability, the value that 90% of future measurements will lie above is 83.72.

What is the value?

It can be found as:

= Mean + (z score x standard deviation)

For a value that 90% will lie above, we use 0.10 where Z will be -1.28.

The value is:

= 85 + (-1.28 x 1)

= 83.72.

Find out more on z scores at https://brainly.com/question/25638875.

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