Answer:
The angular magnification is [tex]M = 2.808[/tex]
Explanation:
From the question we are told
      The focal length is  [tex]f = 8.9cm[/tex]
     The near point is [tex]n_p = 25.0cm[/tex]
The angular magnification is mathematically represented as
             [tex]M = \frac{n_p}{f}[/tex]
Substituting values
            [tex]M = \frac{25}{8.9}[/tex]
              [tex]= 2.808[/tex]