Answer:
The final temperature of the system is 39⁰C
Explanation:
Applying principle of conservation of heat energy;
Heat loss by a hot body = heat gained by a cold body
[tex]m_hc(T_i_h -T) = m_c(T-T_i_c)[/tex]
where;
Mh is the mass of the hot fluid = 330 g = 0.33 kg
Mc is the mass of the cold fluid = 855-g = 0.855 kg
Tih is the initial temperature of the hot fluid = 55°C
Tic is the initial temperature of the cold fluid = 10°C
T is the final temperature of the mixture
Substitute the given values and solve for T
[tex]m_hc(T_i_h -T) = m_c(T-T_i_c)\\\\0.33*4190(55 -T) = 0.855*900(T-10)\\\\1382.7(55 -T) = 769.5(T-10)\\\\(T-10) = 1.797(55 -T)\\\\T-10 = 98.835 - 1.797T\\\\T+ 1.797T = 98.835 + 10\\\\2.797T= 108.835\\\\T = \frac{108.835}{2.797} = 39^o C[/tex]
Therefore, the final temperature of the system is 39⁰C
