The value in the denominator of the solution is 2.
So option A is the correct answer.
The given quadratic equation is  2[tex]x^{2}[/tex] + 10x - 6 = 0.
We need to find the value of the denominator of the solution of the given quadratic equation using the quadratic formula.
What is the quadratic formula?
A quadratic equation in the form  a[tex]x^{2}[/tex] + bx + c = 0  has a quadratic formula as:
The quadratic formula is given as:
[tex]x = \frac{-b~^+_-\sqrt{b^{2}-4ac } }{2a}[/tex]
We have the quadratic equation as :
 2[tex]x^{2}[/tex] + 10x - 6 = 0.
Here a = 2, b = 10 and c = - 6.
Substituting the value of a, b, and c in the quadratic formula.
we get,
x = ( - 10 ± [tex]\sqrt{10^2-4\times2\times-6}[/tex] ) / 2 x 2
x = ( -10 ± [tex]\sqrt{100 + 48}[/tex] ) / 4
x = ( -10 ± [tex]\sqrt{148}[/tex] ) / 4
x = (-10 ± 2 [tex]\sqrt{37}[/tex] ) / 4
x = 2[-5 ± [tex]\sqrt{37}[/tex]] / 4
x = (-5 ± [tex]\sqrt{37}[/tex]) / 2
Thus we see that the value of the denominator of the solution for the given quadratic equation is 2.
Learn more about the solution of quadratic equations here:
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