Answer:
Step-by-step explanation:
Some information in this question is missing as we are not given with the probability p that any weaving machine will break down anytime. Â
For solving this question, Suppose the probability p  = 0.2
n = no. of machines
p = probability of breaking  at any time and
x = the number of successes and
Let A be a random variable that denotes the number of weaving machines that will break down.
A follows binomial distribution with n = 8 and p = 0.2
We will use the formula P(A=x) = nCx * [tex]p^{x}[/tex] * [tex](1-p)^{n-x}[/tex]
Now, the probability that at any given time none of the weaving machines will be broken down:
P (A=0) = 8C0 * [tex]0.2^{0}[/tex] * [tex](1-0.2)^{8-0}[/tex]
P = 1 * 1 * 0.1677
P (A=0) = 0.1677
So, the probability that at any given time none of the weaving machines will be broken down is 0.1677.